Posted on July 2nd, 2012 at 10:02 by Desiato in category: Funny! -- Write a comment
If the (random) answer was either a) or d) the answer would be 25% (for both a) and d) say so) but the chances of hitting a) or d) would actually be 50%. So a) and d) are wrong. The same goes for b) and d). In short a random selection has a chance of 50% to pick 25%, 25% to pick 50% and 25% to pick 60%. So the correct answer is 0% which is not in the list. Not that it would help to put it in the list.
But isn’t the correct answer itself partially dependent on the choices everyone answering make it?
@Mudak the assumption is that others answer at random too.
Define “the right answer” as the one reflected in the answer key… there is exactly one chance in four of choosing the response that matches the answer key, all that matters in a multiple-guess question.
@SteveG: since “1 in 4″ means 25%, that logic leads you straight to Jan-Mark’s answer in #1. (Not that I agree that is the correct answer… )
The answer is “almost zero.”
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